Class Practice (III) Our discussion on 24 APRIL

During the lesson, we looked at how (a) and (b) can be simplified using single fraction.

We learnt that while the approach could be different, both methods give the same answers (though they look different). We can also show how one answer is equivalent to the other.

For (c), the approach is similar to the following arithmetic example. When it is a product, we can expand the three factors in any order.

• 2 x 3 x 5 = (2 x 3) x 5 OR 2 x (3 x 5) OR (2 x 5) x 3